Optimal. Leaf size=145 \[ -\frac{\left (d^2-e^2 x^2\right )^{p-1}}{3 x^3}-\frac{2 e^2 (4-p) \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \left (d^2-e^2 x^2\right )^p \, _2F_1\left (-\frac{1}{2},2-p;\frac{1}{2};\frac{e^2 x^2}{d^2}\right )}{3 d^4 x}-\frac{e^3 \left (d^2-e^2 x^2\right )^{p-1} \, _2F_1\left (2,p-1;p;1-\frac{e^2 x^2}{d^2}\right )}{d^3 (1-p)} \]
[Out]
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Rubi [A] time = 0.380129, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.28 \[ -\frac{\left (d^2-e^2 x^2\right )^{p-1}}{3 x^3}-\frac{2 e^2 (4-p) \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \left (d^2-e^2 x^2\right )^p \, _2F_1\left (-\frac{1}{2},2-p;\frac{1}{2};\frac{e^2 x^2}{d^2}\right )}{3 d^4 x}-\frac{e^3 \left (d^2-e^2 x^2\right )^{p-1} \, _2F_1\left (2,p-1;p;1-\frac{e^2 x^2}{d^2}\right )}{d^3 (1-p)} \]
Antiderivative was successfully verified.
[In] Int[(d^2 - e^2*x^2)^p/(x^4*(d + e*x)^2),x]
[Out]
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Rubi in Sympy [A] time = 62.504, size = 146, normalized size = 1.01 \[ - \frac{\left (1 - \frac{e^{2} x^{2}}{d^{2}}\right )^{- p} \left (d^{2} - e^{2} x^{2}\right )^{p}{{}_{2}F_{1}\left (\begin{matrix} - p + 2, - \frac{3}{2} \\ - \frac{1}{2} \end{matrix}\middle |{\frac{e^{2} x^{2}}{d^{2}}} \right )}}{3 d^{2} x^{3}} - \frac{e^{3} \left (d^{2} - e^{2} x^{2}\right )^{p - 1}{{}_{2}F_{1}\left (\begin{matrix} 2, p - 1 \\ p \end{matrix}\middle |{1 - \frac{e^{2} x^{2}}{d^{2}}} \right )}}{d^{3} \left (- p + 1\right )} - \frac{e^{2} \left (1 - \frac{e^{2} x^{2}}{d^{2}}\right )^{- p} \left (d^{2} - e^{2} x^{2}\right )^{p}{{}_{2}F_{1}\left (\begin{matrix} - p + 2, - \frac{1}{2} \\ \frac{1}{2} \end{matrix}\middle |{\frac{e^{2} x^{2}}{d^{2}}} \right )}}{d^{4} x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((-e**2*x**2+d**2)**p/x**4/(e*x+d)**2,x)
[Out]
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Mathematica [B] time = 0.602752, size = 334, normalized size = 2.3 \[ \frac{\left (d^2-e^2 x^2\right )^p \left (-\frac{36 d^2 e^2 \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (-\frac{1}{2},-p;\frac{1}{2};\frac{e^2 x^2}{d^2}\right )}{x}-\frac{24 d e^3 \left (1-\frac{d^2}{e^2 x^2}\right )^{-p} \, _2F_1\left (-p,-p;1-p;\frac{d^2}{e^2 x^2}\right )}{p}-\frac{4 d^4 \left (1-\frac{e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (-\frac{3}{2},-p;-\frac{1}{2};\frac{e^2 x^2}{d^2}\right )}{x^3}-\frac{12 d^3 e \left (1-\frac{d^2}{e^2 x^2}\right )^{-p} \, _2F_1\left (1-p,-p;2-p;\frac{d^2}{e^2 x^2}\right )}{(p-1) x^2}+\frac{3 e^3 2^{p+3} (e x-d) \left (\frac{e x}{d}+1\right )^{-p} \, _2F_1\left (1-p,p+1;p+2;\frac{d-e x}{2 d}\right )}{p+1}+\frac{3 e^3 2^p (e x-d) \left (\frac{e x}{d}+1\right )^{-p} \, _2F_1\left (2-p,p+1;p+2;\frac{d-e x}{2 d}\right )}{p+1}\right )}{12 d^6} \]
Antiderivative was successfully verified.
[In] Integrate[(d^2 - e^2*x^2)^p/(x^4*(d + e*x)^2),x]
[Out]
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Maple [F] time = 0.109, size = 0, normalized size = 0. \[ \int{\frac{ \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{p}}{{x}^{4} \left ( ex+d \right ) ^{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((-e^2*x^2+d^2)^p/x^4/(e*x+d)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{p}}{{\left (e x + d\right )}^{2} x^{4}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-e^2*x^2 + d^2)^p/((e*x + d)^2*x^4),x, algorithm="maxima")
[Out]
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{p}}{e^{2} x^{6} + 2 \, d e x^{5} + d^{2} x^{4}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-e^2*x^2 + d^2)^p/((e*x + d)^2*x^4),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{p}}{x^{4} \left (d + e x\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-e**2*x**2+d**2)**p/x**4/(e*x+d)**2,x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{p}}{{\left (e x + d\right )}^{2} x^{4}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-e^2*x^2 + d^2)^p/((e*x + d)^2*x^4),x, algorithm="giac")
[Out]